3[2(x+1)+1]-8x=

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Solution for 3[2(x+1)+1]-8x= equation:


Simplifying
3[2(x + 1) + 1] + -8x = 0

Reorder the terms:
3[2(1 + x) + 1] + -8x = 0
3[(1 * 2 + x * 2) + 1] + -8x = 0
3[(2 + 2x) + 1] + -8x = 0

Reorder the terms:
3[2 + 1 + 2x] + -8x = 0

Combine like terms: 2 + 1 = 3
3[3 + 2x] + -8x = 0
[3 * 3 + 2x * 3] + -8x = 0
[9 + 6x] + -8x = 0

Combine like terms: 6x + -8x = -2x
9 + -2x = 0

Solving
9 + -2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -2x = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -2x = 0 + -9
-2x = 0 + -9

Combine like terms: 0 + -9 = -9
-2x = -9

Divide each side by '-2'.
x = 4.5

Simplifying
x = 4.5

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